2026-06-26
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Puzzle guide
Full breakdown using the Solver walkthrough format — checkpoint hops, corridor notes, wall map, and strategy notes.
Overview
LinkedIn Zip #466 is the LinkedIn Zip daily for June 26, 2026. Zip is LinkedIn's path puzzle: draw one continuous route through a 7×7 grid, visit every cell exactly once, hit 9 numbered checkpoints in order, and navigate around 6 walls. This page includes the live board, a solved-board view, and a step-by-step Solution walkthrough. Difficulty: Hard. Estimated solve time: 6–10 min.
Answer
This 7×7 Zip route visits all 49 cells once, hits 9 checkpoints in order, and respects 6 walls:
1→2 (13 cells, R6C4→R1C5); 2→3 (7 cells, R1C5→R6C6); 3→4 (3 cells, R6C6→R5C5); 4→5 (5 cells, R5C5→R3C3); 5→6 (3 cells, R3C3→R2C4); 6→7 (15 cells, R2C4→R7C3); 7→8 (5 cells, R7C3→R4C4); 8→9 (5 cells, R4C4→R2C2)
Checkpoints sit close together on the grid — short numbered hops still need full-cell coverage between them without revisiting squares.
Analysis
I solve LinkedIn Zip #466 checkpoint by checkpoint on a 7×7 grid. 9 numbers to hit in sequence, 6 walls to respect. My route breaks into 8 hops: 1→2 (13 cells), 2→3 (7 cells), 3→4 (3 cells), 4→5 (5 cells), 5→6 (3 cells), 6→7 (15 cells), 7→8 (5 cells), 8→9 (5 cells).
Before the first stroke I mark walls and the next checkpoint — on this board that means Checkpoints sit close together on the grid — short numbered hops still need full-cell coverage between them without revisiting squares.
I draw hop 1 next — checkpoint 2 at R1C5 after 13 cells from R6C4. Open corridor — no walls on this hop.
I draw hop 2 next — checkpoint 3 at R6C6 after 7 cells from R1C5. Open corridor — no walls on this hop.
I draw hop 3 next — checkpoint 4 at R5C5 after 3 cells from R6C6. Open corridor — no walls on this hop.
I draw hop 4 next — checkpoint 5 at R3C3 after 5 cells from R5C5. Open corridor — no walls on this hop.
I draw hop 5 next — checkpoint 6 at R2C4 after 3 cells from R3C3. Open corridor — no walls on this hop.
I draw hop 6 next — checkpoint 7 at R7C3 after 15 cells from R2C4. Open corridor — no walls on this hop.
I draw hop 7 next — checkpoint 8 at R4C4 after 5 cells from R7C3. Open corridor — no walls on this hop.
I draw hop 8 next — checkpoint 9 at R2C2 after 5 cells from R4C4. Open corridor — no walls on this hop.
Finished — every cell filled, no revisits, walls respected. Checkpoints sit close together on the grid — short numbered hops still need full-cell coverage between them without revisiting squares.
Checkpoint hops
Corridor insight
I route First stretch toward checkpoint 2 at R1C5. 13 cells link checkpoint 1 at R6C4 to checkpoint 2 at R1C5 with open corridors (no walls on this segment).
Solving note
First stretch: Lock this hop before sketching later detours — 13 cells, 0 walls.
Corridor insight
I route Second stretch toward checkpoint 3 at R6C6. 7 cells link checkpoint 2 at R1C5 to checkpoint 3 at R6C6 with open corridors (no walls on this segment).
Solving note
Second stretch: Lock this hop before sketching later detours — 7 cells, 0 walls.
Corridor insight
I route Third stretch toward checkpoint 4 at R5C5. Tight 3-cell hop — checkpoints 3 and 4 sit near each other; still visit every intervening cell exactly once.
Solving note
Third stretch: Lock this hop before sketching later detours — 3 cells, 0 walls.
Corridor insight
I route Fourth stretch toward checkpoint 5 at R3C3. 5 cells link checkpoint 4 at R5C5 to checkpoint 5 at R3C3 with open corridors (no walls on this segment).
Solving note
Fourth stretch: Lock this hop before sketching later detours — 5 cells, 0 walls.
Corridor insight
I route Fifth stretch toward checkpoint 6 at R2C4. Tight 3-cell hop — checkpoints 5 and 6 sit near each other; still visit every intervening cell exactly once.
Solving note
Fifth stretch: Lock this hop before sketching later detours — 3 cells, 0 walls.
Corridor insight
I route Sixth stretch toward checkpoint 7 at R7C3. 15 cells link checkpoint 6 at R2C4 to checkpoint 7 at R7C3 with open corridors (no walls on this segment).
Solving note
Sixth stretch: Lock this hop before sketching later detours — 15 cells, 0 walls.
Corridor insight
I route Seventh stretch toward checkpoint 8 at R4C4. 5 cells link checkpoint 7 at R7C3 to checkpoint 8 at R4C4 with open corridors (no walls on this segment).
Solving note
Seventh stretch: Lock this hop before sketching later detours — 5 cells, 0 walls.
Corridor insight
I route Eighth stretch toward checkpoint 9 at R2C2. 5 cells link checkpoint 8 at R4C4 to checkpoint 9 at R2C2 with open corridors (no walls on this segment).
Solving note
Eighth stretch: Lock this hop before sketching later detours — 5 cells, 0 walls.
Verification
I trust this route because every hop I reveal still allows a full fill — 8 segments, 49 cells total. Wrong early detours dead-end against walls or trap unchecked squares.
Solve path
Phase 1: Start at checkpoint 1 (R6C4) on this 7×7 grid with 9 checkpoints and 6 walls. Segment 1: Visit checkpoint 2 at R1C5 via 13 cells from checkpoint 1. 13 cells link checkpoint 1 at R6C4 to checkpoint 2 at R1C5 with open corridors (no walls on this segment). Segment 2: Visit checkpoint 3 at R6C6 via 7 cells from checkpoint 2. 7 cells link checkpoint 2 at R1C5 to checkpoint 3 at R6C6 with open corridors (no walls on this segment). Segment 3: Visit checkpoint 4 at R5C5 via 3 cells from checkpoint 3. Tight 3-cell hop — checkpoints 3 and 4 sit near each other; still visit every intervening cell exactly once. Segment 4: Visit checkpoint 5 at R3C3 via 5 cells from checkpoint 4. 5 cells link checkpoint 4 at R5C5 to checkpoint 5 at R3C3 with open corridors (no walls on this segment). Segment 5: Visit checkpoint 6 at R2C4 via 3 cells from checkpoint 5. Tight 3-cell hop — checkpoints 5 and 6 sit near each other; still visit every intervening cell exactly once. Segment 6: Visit checkpoint 7 at R7C3 via 15 cells from checkpoint 6. 15 cells link checkpoint 6 at R2C4 to checkpoint 7 at R7C3 with open corridors (no walls on this segment). Segment 7: Visit checkpoint 8 at R4C4 via 5 cells from checkpoint 7. 5 cells link checkpoint 7 at R7C3 to checkpoint 8 at R4C4 with open corridors (no walls on this segment). Segment 8: Visit checkpoint 9 at R2C2 via 5 cells from checkpoint 8. 5 cells link checkpoint 8 at R4C4 to checkpoint 9 at R2C2 with open corridors (no walls on this segment). Complete: Hamiltonian path covers all 49 cells, checkpoints 1–9 in order, ending on checkpoint 9 at R2C2.
Pattern
Checkpoints sit close together on the grid — short numbered hops still need full-cell coverage between them without revisiting squares.
Learn more in Zip Puzzle Strategies →Takeaways
Mapping checkpoint 9 early made the final sweep obvious. 8 reveals matched how I think while playing.
Longest hop: 15 cells — if a segment feels longer, you are probably on the archive path.
Try LinkedIn Zip #466 again using one hint max per stuck segment — walls (6) matter most on hops 2 and 3.
Solution
This 7×7 board has 9 checkpoints (1@R6C4, 2@R1C5, 3@R6C6, 4@R5C5, 5@R3C3, 6@R2C4, 7@R7C3, 8@R4C4, 9@R2C2) and 6 walls. The solution path covers 49 cells in 8 checkpoint hops: 1→2 (13 cells, R6C4→R1C5); 2→3 (7 cells, R1C5→R6C6); 3→4 (3 cells, R6C6→R5C5); 4→5 (5 cells, R5C5→R3C3); 5→6 (3 cells, R3C3→R2C4); 6→7 (15 cells, R2C4→R7C3); 7→8 (5 cells, R7C3→R4C4); 8→9 (5 cells, R4C4→R2C2). Checkpoints sit close together on the grid — short numbered hops still need full-cell coverage between them without revisiting squares. Use the Solution tab for a checkpoint-segment reveal with live board updates, or the Solved board tab for the complete path at a glance.