LinkedIn Zip #469

LinkedIn Zip #469 is the LinkedIn Zip daily for June 29, 2026. Zip is LinkedIn's path puzzle: draw one continuous route through a 6×6 grid, visit every cell exactly once, hit 13 numbered checkpoints in order, and navigate around 0 walls. This page includes the live board, a solved-board view, and a step-by-step Solution walkthrough. Difficulty: Easy. Estimated solve time: 3–5 min.

This 6×6 Zip route visits all 36 cells once, hits 13 checkpoints in order, and respects 0 walls:

1→2 (3 cells, R1C3→R1C1); 2→3 (3 cells, R1C1→R3C1); 3→4 (5 cells, R3C1→R5C3); 4→5 (2 cells, R5C3→R5C2); 5→6 (2 cells, R5C2→R5C1); 6→7 (13 cells, R5C1→R1C5); 7→8 (4 cells, R1C5→R2C3); 8→9 (3 cells, R2C3→R3C2); 9→10 (5 cells, R3C2→R5C4); 10→11 (3 cells, R5C4→R4C5); 11→12 (2 cells, R4C5→R3C5); 12→13 (2 cells, R3C5→R2C5)

Checkpoints sit close together on the grid — short numbered hops still need full-cell coverage between them without revisiting squares.

1. Hop 1Sample 1Checkpoint 1 → 2 (3 cells)

   Corridor insight

   Sample 1: 1→2, length 3, walls 0.

   Solving note

   Tight 3-cell hop — checkpoints 1 and 2 sit near each other; still visit every intervening cell exactly once.

2. Hop 2Sample 2Checkpoint 2 → 3 (3 cells)

   Corridor insight

   Sample 2: 2→3, length 3, walls 0.

   Solving note

   Tight 3-cell hop — checkpoints 2 and 3 sit near each other; still visit every intervening cell exactly once.

3. Hop 3Sample 3Checkpoint 3 → 4 (5 cells)

   Corridor insight

   Sample 3: 3→4, length 5, walls 0.

   Solving note

   5 cells link checkpoint 3 at R3C1 to checkpoint 4 at R5C3 with open corridors (no walls on this segment).

4. Hop 4Sample 4Checkpoint 4 → 5 (2 cells)

   Corridor insight

   Sample 4: 4→5, length 2, walls 0.

   Solving note

   Tight 2-cell hop — checkpoints 4 and 5 sit near each other; still visit every intervening cell exactly once.

5. Hop 5Sample 5Checkpoint 5 → 6 (2 cells)

   Corridor insight

   Sample 5: 5→6, length 2, walls 0.

   Solving note

   Tight 2-cell hop — checkpoints 5 and 6 sit near each other; still visit every intervening cell exactly once.

6. Hop 6Sample 6Checkpoint 6 → 7 (13 cells)

   Corridor insight

   Sample 6: 6→7, length 13, walls 0.

   Solving note

   Long 13-cell sweep (36% of the board) from checkpoint 6 to 7 — most of the Hamiltonian path lives in this detour.

7. Hop 7Sample 7Checkpoint 7 → 8 (4 cells)

   Corridor insight

   Sample 7: 7→8, length 4, walls 0.

   Solving note

   4 cells link checkpoint 7 at R1C5 to checkpoint 8 at R2C3 with open corridors (no walls on this segment).

8. Hop 8Sample 8Checkpoint 8 → 9 (3 cells)

   Corridor insight

   Sample 8: 8→9, length 3, walls 0.

   Solving note

   Tight 3-cell hop — checkpoints 8 and 9 sit near each other; still visit every intervening cell exactly once.

9. Hop 9Hop 9Checkpoint 9 → 10 (5 cells)

   Corridor insight

   Hop 9: 9→10, length 5, walls 0.

   Solving note

   5 cells link checkpoint 9 at R3C2 to checkpoint 10 at R5C4 with open corridors (no walls on this segment).

10. Hop 10Hop 10Checkpoint 10 → 11 (3 cells)

    Corridor insight

    Hop 10: 10→11, length 3, walls 0.

    Solving note

    Tight 3-cell hop — checkpoints 10 and 11 sit near each other; still visit every intervening cell exactly once.

11. Hop 11Hop 11Checkpoint 11 → 12 (2 cells)

    Corridor insight

    Hop 11: 11→12, length 2, walls 0.

    Solving note

    Tight 2-cell hop — checkpoints 11 and 12 sit near each other; still visit every intervening cell exactly once.

12. Hop 12Hop 12Checkpoint 12 → 13 (2 cells)

    Corridor insight

    Hop 12: 12→13, length 2, walls 0.

    Solving note

    Tight 2-cell hop — checkpoints 12 and 13 sit near each other; still visit every intervening cell exactly once.

Optimal segment vector: 1→2 (3 cells, R1C3→R1C1); 2→3 (3 cells, R1C1→R3C1); 3→4 (5 cells, R3C1→R5C3); 4→5 (2 cells, R5C3→R5C2); 5→6 (2 cells, R5C2→R5C1); 6→7 (13 cells, R5C1→R1C5); 7→8 (4 cells, R1C5→R2C3); 8→9 (3 cells, R2C3→R3C2); 9→10 (5 cells, R3C2→R5C4); 10→11 (3 cells, R5C4→R4C5); 11→12 (2 cells, R4C5→R3C5); 12→13 (2 cells, R3C5→R2C5). Wall budget 0. Pattern class checkpointCluster.

Phase 1: Start at checkpoint 1 (R1C3) on this 6×6 grid with 13 checkpoints and 0 walls. Segment 1: Visit checkpoint 2 at R1C1 via 3 cells from checkpoint 1. Tight 3-cell hop — checkpoints 1 and 2 sit near each other; still visit every intervening cell exactly once. Segment 2: Visit checkpoint 3 at R3C1 via 3 cells from checkpoint 2. Tight 3-cell hop — checkpoints 2 and 3 sit near each other; still visit every intervening cell exactly once. Segment 3: Visit checkpoint 4 at R5C3 via 5 cells from checkpoint 3. 5 cells link checkpoint 3 at R3C1 to checkpoint 4 at R5C3 with open corridors (no walls on this segment). Segment 4: Visit checkpoint 5 at R5C2 via 2 cells from checkpoint 4. Tight 2-cell hop — checkpoints 4 and 5 sit near each other; still visit every intervening cell exactly once. Segment 5: Visit checkpoint 6 at R5C1 via 2 cells from checkpoint 5. Tight 2-cell hop — checkpoints 5 and 6 sit near each other; still visit every intervening cell exactly once. Segment 6: Visit checkpoint 7 at R1C5 via 13 cells from checkpoint 6. Long 13-cell sweep (36% of the board) from checkpoint 6 to 7 — most of the Hamiltonian path lives in this detour. Segment 7: Visit checkpoint 8 at R2C3 via 4 cells from checkpoint 7. 4 cells link checkpoint 7 at R1C5 to checkpoint 8 at R2C3 with open corridors (no walls on this segment). Segment 8: Visit checkpoint 9 at R3C2 via 3 cells from checkpoint 8. Tight 3-cell hop — checkpoints 8 and 9 sit near each other; still visit every intervening cell exactly once. Segment 9: Visit checkpoint 10 at R5C4 via 5 cells from checkpoint 9. 5 cells link checkpoint 9 at R3C2 to checkpoint 10 at R5C4 with open corridors (no walls on this segment). Segment 10: Visit checkpoint 11 at R4C5 via 3 cells from checkpoint 10. Tight 3-cell hop — checkpoints 10 and 11 sit near each other; still visit every intervening cell exactly once. Segment 11: Visit checkpoint 12 at R3C5 via 2 cells from checkpoint 11. Tight 2-cell hop — checkpoints 11 and 12 sit near each other; still visit every intervening cell exactly once. Segment 12: Visit checkpoint 13 at R2C5 via 2 cells from checkpoint 12. Tight 2-cell hop — checkpoints 12 and 13 sit near each other; still visit every intervening cell exactly once. Complete: Hamiltonian path covers all 36 cells, checkpoints 1–13 in order, ending on checkpoint 13 at R2C5.

Checkpoints sit close together on the grid — short numbered hops still need full-cell coverage between them without revisiting squares.

This 6×6 board has 13 checkpoints (1@R1C3, 2@R1C1, 3@R3C1, 4@R5C3, 5@R5C2, 6@R5C1, 7@R1C5, 8@R2C3, 9@R3C2, 10@R5C4, 11@R4C5, 12@R3C5, 13@R2C5) and 0 walls. The solution path covers 36 cells in 12 checkpoint hops: 1→2 (3 cells, R1C3→R1C1); 2→3 (3 cells, R1C1→R3C1); 3→4 (5 cells, R3C1→R5C3); 4→5 (2 cells, R5C3→R5C2); 5→6 (2 cells, R5C2→R5C1); 6→7 (13 cells, R5C1→R1C5); 7→8 (4 cells, R1C5→R2C3); 8→9 (3 cells, R2C3→R3C2); 9→10 (5 cells, R3C2→R5C4); 10→11 (3 cells, R5C4→R4C5); 11→12 (2 cells, R4C5→R3C5); 12→13 (2 cells, R3C5→R2C5). Checkpoints sit close together on the grid — short numbered hops still need full-cell coverage between them without revisiting squares. Use the Solution tab for a checkpoint-segment reveal with live board updates, or the Solved board tab for the complete path at a glance.