LinkedIn Zip #499

LinkedIn Zip #499 is the LinkedIn Zip daily for July 29, 2026. Zip is LinkedIn's path puzzle: draw one continuous route through a 6×6 grid, visit every cell exactly once, hit 10 numbered checkpoints in order, and navigate around 0 walls. This page includes the live board, a solved-board view, and a step-by-step Solution walkthrough. Difficulty: Medium. Estimated solve time: 4–6 min.

This 6×6 Zip route visits all 36 cells once, hits 10 checkpoints in order, and respects 0 walls:

1→2 (2 cells, R6C3→R6C4); 2→3 (3 cells, R6C4→R6C6); 3→4 (8 cells, R6C6→R6C1); 4→5 (8 cells, R6C1→R4C6); 5→6 (4 cells, R4C6→R1C6); 6→7 (8 cells, R1C6→R3C1); 7→8 (6 cells, R3C1→R1C4); 8→9 (2 cells, R1C4→R1C3); 9→10 (3 cells, R1C3→R1C1)

Checkpoints sit close together on the grid — short numbered hops still need full-cell coverage between them without revisiting squares.

1. Hop 1Sample 1Checkpoint 1 → 2 (2 cells)

   Corridor insight

   Sample 1: 1→2, length 2, walls 0.

   Solving note

   Tight 2-cell hop — checkpoints 1 and 2 sit near each other; still visit every intervening cell exactly once.

2. Hop 2Sample 2Checkpoint 2 → 3 (3 cells)

   Corridor insight

   Sample 2: 2→3, length 3, walls 0.

   Solving note

   Tight 3-cell hop — checkpoints 2 and 3 sit near each other; still visit every intervening cell exactly once.

3. Hop 3Sample 3Checkpoint 3 → 4 (8 cells)

   Corridor insight

   Sample 3: 3→4, length 8, walls 0.

   Solving note

   8 cells link checkpoint 3 at R6C6 to checkpoint 4 at R6C1 with open corridors (no walls on this segment).

4. Hop 4Sample 4Checkpoint 4 → 5 (8 cells)

   Corridor insight

   Sample 4: 4→5, length 8, walls 0.

   Solving note

   8 cells link checkpoint 4 at R6C1 to checkpoint 5 at R4C6 with open corridors (no walls on this segment).

5. Hop 5Sample 5Checkpoint 5 → 6 (4 cells)

   Corridor insight

   Sample 5: 5→6, length 4, walls 0.

   Solving note

   4 cells link checkpoint 5 at R4C6 to checkpoint 6 at R1C6 with open corridors (no walls on this segment).

6. Hop 6Sample 6Checkpoint 6 → 7 (8 cells)

   Corridor insight

   Sample 6: 6→7, length 8, walls 0.

   Solving note

   8 cells link checkpoint 6 at R1C6 to checkpoint 7 at R3C1 with open corridors (no walls on this segment).

7. Hop 7Sample 7Checkpoint 7 → 8 (6 cells)

   Corridor insight

   Sample 7: 7→8, length 6, walls 0.

   Solving note

   6 cells link checkpoint 7 at R3C1 to checkpoint 8 at R1C4 with open corridors (no walls on this segment).

8. Hop 8Sample 8Checkpoint 8 → 9 (2 cells)

   Corridor insight

   Sample 8: 8→9, length 2, walls 0.

   Solving note

   Tight 2-cell hop — checkpoints 8 and 9 sit near each other; still visit every intervening cell exactly once.

9. Hop 9Hop 9Checkpoint 9 → 10 (3 cells)

   Corridor insight

   Hop 9: 9→10, length 3, walls 0.

   Solving note

   Tight 3-cell hop — checkpoints 9 and 10 sit near each other; still visit every intervening cell exactly once.

Optimal segment vector: 1→2 (2 cells, R6C3→R6C4); 2→3 (3 cells, R6C4→R6C6); 3→4 (8 cells, R6C6→R6C1); 4→5 (8 cells, R6C1→R4C6); 5→6 (4 cells, R4C6→R1C6); 6→7 (8 cells, R1C6→R3C1); 7→8 (6 cells, R3C1→R1C4); 8→9 (2 cells, R1C4→R1C3); 9→10 (3 cells, R1C3→R1C1). Wall budget 0. Pattern class checkpointCluster.

Phase 1: Start at checkpoint 1 (R6C3) on this 6×6 grid with 10 checkpoints and 0 walls. Segment 1: Visit checkpoint 2 at R6C4 via 2 cells from checkpoint 1. Tight 2-cell hop — checkpoints 1 and 2 sit near each other; still visit every intervening cell exactly once. Segment 2: Visit checkpoint 3 at R6C6 via 3 cells from checkpoint 2. Tight 3-cell hop — checkpoints 2 and 3 sit near each other; still visit every intervening cell exactly once. Segment 3: Visit checkpoint 4 at R6C1 via 8 cells from checkpoint 3. 8 cells link checkpoint 3 at R6C6 to checkpoint 4 at R6C1 with open corridors (no walls on this segment). Segment 4: Visit checkpoint 5 at R4C6 via 8 cells from checkpoint 4. 8 cells link checkpoint 4 at R6C1 to checkpoint 5 at R4C6 with open corridors (no walls on this segment). Segment 5: Visit checkpoint 6 at R1C6 via 4 cells from checkpoint 5. 4 cells link checkpoint 5 at R4C6 to checkpoint 6 at R1C6 with open corridors (no walls on this segment). Segment 6: Visit checkpoint 7 at R3C1 via 8 cells from checkpoint 6. 8 cells link checkpoint 6 at R1C6 to checkpoint 7 at R3C1 with open corridors (no walls on this segment). Segment 7: Visit checkpoint 8 at R1C4 via 6 cells from checkpoint 7. 6 cells link checkpoint 7 at R3C1 to checkpoint 8 at R1C4 with open corridors (no walls on this segment). Segment 8: Visit checkpoint 9 at R1C3 via 2 cells from checkpoint 8. Tight 2-cell hop — checkpoints 8 and 9 sit near each other; still visit every intervening cell exactly once. Segment 9: Visit checkpoint 10 at R1C1 via 3 cells from checkpoint 9. Tight 3-cell hop — checkpoints 9 and 10 sit near each other; still visit every intervening cell exactly once. Complete: Hamiltonian path covers all 36 cells, checkpoints 1–10 in order, ending on checkpoint 10 at R1C1.

Checkpoints sit close together on the grid — short numbered hops still need full-cell coverage between them without revisiting squares.

This 6×6 board has 10 checkpoints (1@R6C3, 2@R6C4, 3@R6C6, 4@R6C1, 5@R4C6, 6@R1C6, 7@R3C1, 8@R1C4, 9@R1C3, 10@R1C1) and 0 walls. The solution path covers 36 cells in 9 checkpoint hops: 1→2 (2 cells, R6C3→R6C4); 2→3 (3 cells, R6C4→R6C6); 3→4 (8 cells, R6C6→R6C1); 4→5 (8 cells, R6C1→R4C6); 5→6 (4 cells, R4C6→R1C6); 6→7 (8 cells, R1C6→R3C1); 7→8 (6 cells, R3C1→R1C4); 8→9 (2 cells, R1C4→R1C3); 9→10 (3 cells, R1C3→R1C1). Checkpoints sit close together on the grid — short numbered hops still need full-cell coverage between them without revisiting squares. Use the Solution tab for a checkpoint-segment reveal with live board updates, or the Solved board tab for the complete path at a glance.